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Ed H
Member
Joined: 30 Nov 2007
Posts: 138
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 Posted: 02 Feb 2010 08:17:07 pm Post subject: |
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So you wanna perform the Extended Euclidean algorithm on two numbers A and B, eh?
Code:
:{1,i,A+Bi
:While imag(Ans(3
:iconj(Ans-imag(Ans)int(real(Ans(3)/imag(Ans(3
:End
:real(Ans
You'll end up with a list {X,Y,C} with XA + YB = C, where C is the GCD of A and B.
On a related note,
Code:
:Ans+i
:While E-9<imag(Ans
:iconj(Ans-imag(Ans)int(real(Ans/imag(Ans
:End
:real(Ans
will pull out the denominator out of a fraction. Not sure if this is new. |
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Weregoose
Authentic INTJ
Super Elite (Last Title)
Joined: 25 Nov 2004
Posts: 3976
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| Posted: 02 Feb 2010 09:54:28 pm Post subject: |
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Aside from my swapping every real( and imag( in this post, we used the exact same method. 
Last edited by Guest on 01 Jul 2010 09:51:54 am; edited 1 time in total |
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Ed H
Member
Joined: 30 Nov 2007
Posts: 138
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| Posted: 04 Feb 2010 12:01:11 am Post subject: |
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| Haha, sweet. I came up with that idea when I realized how repetitive the operations in the extended Euclidean algorithm were. I wanted to take advantage of this by using lists for the variables X, Y, and A/B, which required me to use complex numbers to store both values in one element. |
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