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2Xist
Newbie
Joined: 15 Apr 2008
Posts: 9
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 Posted: 06 May 2008 07:05:38 pm Post subject: |
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Hi,
again as usual, i unfortunally have another question about the ti-89 titanum
when i insert (x^2)^2 i get x^4 (due to the power law in expoents) but when i insert (x^2)^y i get the same answer back, (x^2)^y. what i think the answer should be is x^2y but i donno whats wrong.
Please try on your own calculators and reply results
thanks again
Last edited by Guest on 06 May 2008 07:05:57 pm; edited 1 time in total |
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2Xist
Newbie
Joined: 15 Apr 2008
Posts: 9
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| Posted: 07 May 2008 02:57:47 pm Post subject: |
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| come on guys.. don't leave a brother hangin |
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DarkerLine
ceci n'est pas une |
Super Elite (Last Title)
Joined: 04 Nov 2003
Posts: 8328
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| Posted: 07 May 2008 03:39:49 pm Post subject: |
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What makes you think anything's wrong? It's an open question whether x^(2*y) is even "more simplified" than (x^2)^y.
Besides, it doesn't always hold for complex numbers. ((-1)^2)^i=1 but (-1)^(2i)=e^(-2[font="times new roman"]π) |
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