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simplethinker snjwffl
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Joined: 25 Jul 2006 Posts: 700
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Posted: 06 Dec 2006 04:00:44 pm Post subject: |
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I need to find the slope of the equation: 50-50cos(1.8x)
after plugging it into (f(x+h)-f(x))/h I got: lim h->0 50(cos(1.8x)-cos(1.8x+1.8h))/h
then: lim h->0 50(cos(1.8x)-cos(1.8x)cos(1.8h)+sin(1.8x)sin(1.8h))/h
lim h->0 50( sin(1.8x)sin(1.8h)/h + cos(x)(1-cos(1.8h))/h )
lim h->0 sin(1.8h)/h = 1.8 : lim h->0 1-cos(1.8h)/h = 0, so it's:
lim h->0 50(1.8sin(1.8x)+0)
take the limit and it's:
90sin(1.8x)
ive gone over the work 3 times and cant find anything wrong but when i punch it in and compare it to (f(x+.0001)-f(x))/.0001 they're way different
anyone have any ideas of what im doing wrong? |
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alexrudd pm me if you read this
Bandwidth Hog
Joined: 06 Oct 2004 Posts: 2335
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Posted: 06 Dec 2006 04:33:09 pm Post subject: |
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I used [2nd] [calc] dy/dx, 90sin(1.8x), and (Y1(2.0001)-Y1(2))/.0001 at x=2 and got about -39 for each. What did you get? |
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simplethinker snjwffl
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Joined: 25 Jul 2006 Posts: 700
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Posted: 06 Dec 2006 05:54:21 pm Post subject: |
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I got -50 for 90sin(1.8x) and 69 for (f(x+.0001)-f(x))/.0001 |
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simplethinker snjwffl
Active Member
Joined: 25 Jul 2006 Posts: 700
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Posted: 06 Dec 2006 05:55:24 pm Post subject: |
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ok, nvm i got it
i was in deg instead of rad mode lol |
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alexrudd pm me if you read this
Bandwidth Hog
Joined: 06 Oct 2004 Posts: 2335
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Posted: 06 Dec 2006 07:13:05 pm Post subject: |
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I was going to suggest checking that, but then realized that both the calculations are in degree mode. Does anyone know why would it make a difference? |
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simplethinker snjwffl
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Joined: 25 Jul 2006 Posts: 700
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Posted: 06 Dec 2006 08:19:59 pm Post subject: |
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For some reason taking the limit of the difference quotient in degrees changes it. I'll ask my teacher tomorrow
Last edited by Guest on 06 Dec 2006 08:23:53 pm; edited 1 time in total |
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Fallen Ghost
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Joined: 15 Jun 2006 Posts: 955
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Posted: 06 Dec 2006 08:23:01 pm Post subject: |
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While looking at a sinusoidal (didn't check the spelling on this) graphing line of equation y=sin(x), being in radians mode will make the space between the peaks of the equation (peaks: y=1 and negative peaks y=-1) is about 5 (something over 4 and under 10) . But in Degree mode, the space between is 360. So when you do sin(5) in radians, it gives
-0.95892427466313846889315440615599, but in degree it will give 0.087155742747658173558064270837474.
I love using the windows calculator in decimal scientific mode (look the number of digits...)
Last edited by Guest on 06 Dec 2006 08:23:12 pm; edited 1 time in total |
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simplethinker snjwffl
Active Member
Joined: 25 Jul 2006 Posts: 700
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Posted: 06 Dec 2006 08:31:37 pm Post subject: |
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The number between 4 and 10 is 6.28 (2*pi). In one rotation there are 360 degrees.
Radians are based on the unit circle, a circle of radius 1 with its center at the origin (equation= (x**2 + y**2)==1 ) the circumference of that circle is 2*pi*r, and since the radius is 1 the circumference is 2*pi. Radians are the arc length, or section of the circumference formed between a angle of n degrees and the x-axis.
You can convert from deg -> rads by multiplying the degrees by pi/180, and rad ->degs by multiplying the rads by180/pi
check this in a calc by pushing in sin(45) in deg mode and sin(pi/4) [45*pi/180==pi/4] in rad, you will get .707 or .5**.5
when calculating sin(5) in radian mode that's calculating sin(5 rads), and 5 radians is about 287 degrees. Punch in sin(287) in degree mode and you'll get what you got for sin(5 rad)
Last edited by Guest on 06 Dec 2006 08:35:54 pm; edited 1 time in total |
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DarkerLine ceci n'est pas une |
Super Elite (Last Title)
Joined: 04 Nov 2003 Posts: 8328
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Posted: 06 Dec 2006 08:43:26 pm Post subject: |
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alexrudd wrote: I was going to suggest checking that, but then realized that both the calculations are in degree mode. Does anyone know why would it make a difference?
[post="92097"]<{POST_SNAPBACK}>[/post] The reason is that the derivative of sine is only cosine when dealing with radians. When you're working with degrees, sin(x°) is really sin(180x/Pi) and the derivative will be 180/Pi*cos(x°) - a significant difference!
There is a reason we use radians, after all. |
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simplethinker snjwffl
Active Member
Joined: 25 Jul 2006 Posts: 700
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Posted: 06 Dec 2006 08:56:38 pm Post subject: |
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Good point, I always forget the derivatives of sin() and cos() are affected by deg/rad even if you have the rads converted to degs |
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