i^N
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Galandros


Active Member


Joined: 29 Aug 2008
Posts: 565
Posted: 21 Apr 2010 08:04:19 am    Post subject:
The smallest code to calculate i^N where N is a integer number (positive or negative).
The answer has to be correct without rounding problems.

1st version:
you can not use round( command.

2nd version:
you cannot use "i^" and similar expressions.

Have fun! (I have a little cheating answer for the first and few idea for the second because I did not have complex numbers in class yet xD)

Last edited by Guest on 21 Apr 2010 01:53:04 pm; edited 1 time in total
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calc84maniac


Elite


Joined: 22 Jan 2007
Posts: 770
Posted: 21 Apr 2010 09:21:15 am    Post subject:
[spoiler]
Code:
:{1,i,-1,-i
:Ans(1+N-4int(N/4
[/spoiler]

Last edited by Guest on 21 Apr 2010 10:46:24 am; edited 1 time in total
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Weregoose
Authentic INTJ


Super Elite (Last Title)


Joined: 25 Nov 2004
Posts: 3976
Posted: 21 Apr 2010 10:45:36 am    Post subject:
Version 1: 17 bytes (no program name)
Version 2: Having trouble getting it to where I'd like it... (The square root is exponentiation!)
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Galandros


Active Member


Joined: 29 Aug 2008
Posts: 565
Posted: 21 Apr 2010 02:09:39 pm    Post subject:
Good answer calcmaniac.
[spoiler]
Although I noticed the pattern, I did not remember to use a Look up List. *facepalm*
[/spoiler]

Weregoose wrote:

Version 1: 17 bytes (no program name)
Version 2: Having trouble getting it to where I'd like it... (The square root is exponentiation!)

I edited the rule to the original restriction I though hours before writing the topic...

Last edited by Guest on 21 Apr 2010 02:18:46 pm; edited 1 time in total
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Weregoose
Authentic INTJ


Super Elite (Last Title)


Joined: 25 Nov 2004
Posts: 3976
Posted: 21 Apr 2010 04:30:26 pm    Post subject:
Here goes:

[spoiler]17 bytes: e^(2[font=times new roman]πifPart(N/4
22 bytes: prod([font=times new roman]inot(0rand(4+4fPart(N/4[/spoiler]
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Galandros


Active Member


Joined: 29 Aug 2008
Posts: 565
Posted: 21 Apr 2010 04:48:34 pm    Post subject:
Answer for 1st teaser version.
[spoiler]
:i^(4fPart(N/4
I do not like the answer but it is valid. 8 bytes.
[/spoiler]

I knew Weregoose or thornahawk would appear with some math trick (talking about the first answer of Weregoose).
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Weregoose
Authentic INTJ


Super Elite (Last Title)


Joined: 25 Nov 2004
Posts: 3976
Posted: 21 Apr 2010 05:26:47 pm    Post subject:
In counting bytes, I read the Mem Mgmt/Del… screen and then subtract the number of characters in the program name (prgmABC has three).

Both yours and mine have the same total.
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thornahawk
μολών λαβέ


Active Member


Joined: 27 Mar 2005
Posts: 569
Posted: 22 Apr 2010 05:19:49 am    Post subject:
Isn't using e^( cheating as well, since ^ uses e^( internally anyway if the second argument is not an integer? ;)

Having said that, I would've taken calc84maniac's approach. ;)

thornahawk
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