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Bwyard
Newbie
Joined: 28 Apr 2009
Posts: 17
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 Posted: 29 Oct 2009 12:49:55 pm Post subject: |
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i created this code to find factors of a number not rpime factors is there a more efficent way to do this. btw LF is list F. and it will work for negative numbers but it doesnt output the factors as negative.
Code:
abs(Ans→X
{1→LF
1→N
1→L
While N≤√X
If fPart(X/N)=0
Then
N→LF(L)
1+L→L
X/N→LF(L)
1+L→L
End
1+N→N
End
SortA(LF)
Last edited by Guest on 29 Oct 2009 12:52:25 pm; edited 1 time in total |
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calcdude84se
Member
Joined: 09 Aug 2009
Posts: 207
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| Posted: 29 Oct 2009 03:55:17 pm Post subject: |
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Right now I cannot think of a way better than your simple one that is not complicated
You can optimize your program in a number of ways. I can give pointers, but I recommend that you look at a site, such as TI-Basic Developer, to give general tips.
A revised version is in the code box below (Ignore things after a ';', they are comments)
Code:
abs(Ans→X;You already had this, but as a general rule, don't use closing marks (",],},) ) at the end of an expression (right before a "→" or at the end of a line)
0→dim(LF;I needed to do this for my changes
1→N;Variable L is unnecessary, its use is covered by "dim(LF"
For(N,1,√X;For( is better than While when it can be easily used
If not(fPart(X/N;An expression "0=..." is the same as "not(..."
Then
N→LF(1+dim(LF;This is shorter than what you had before
X/N→LF(1+dim(LF;Same here
End
End
If not(fPart(√X;Prevent one factor from showing up twice if the number is a perfect square
dim(LF)-1→dim(LF
SortA(LF;No parentheses!
That's about all the optimizations I can think of... |
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Bwyard
Newbie
Joined: 28 Apr 2009
Posts: 17
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| Posted: 29 Oct 2009 04:11:59 pm Post subject: |
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| ok thanks and btw i thought i had the code in there to prevent square roots form being duplicated but i guess not i think i deleted it on accidenta nd didnt replace it. |
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