What is limit of
cos(x)/((e^x)-1+1)
as x approaches 0.
I only know the basics so please explain.
cos(x)/((e^x)-1+1)
as x approaches 0.
I only know the basics so please explain.
Wolfram Alpha can calculate that for you:
http://www.wolframalpha.com/input/?i=cos%28x%29/%28%28e%5Ex%29-1%2B1%29+limit+-%3E+0
http://www.wolframalpha.com/input/?i=cos%28x%29/%28%28e%5Ex%29-1%2B1%29+limit+-%3E+0
You can solve it by simple substitution. cos(0) = 1, e^0 = 1, and -1+1=0. That leaves you with 1/(1-1+1) = 1.
My mistake Kerm. Can you go to number 74 on this website:
http://www.aatm.org/pdf/State_Test_2009wa.pdf
http://www.aatm.org/pdf/State_Test_2009wa.pdf
Simple substitution now results in division by zero. Fortunately, the problem is just asking what value you can draw infinitely towards as x approaches 0. It can be done intuitively in this case, and Kerm's post is enough of a hint towards the solution.
Register to Join the Conversation
You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot vote in polls in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot vote in polls in this forum
Advertisement