Hi
I have ∫4_-4 f(x) dx that i want to solve.
The primitive function: x²/2
4²/2 - (-4)²/2 = 0
I solved the integral in my Prizm and it returned 0 but te book says the awnser is 13.
In the work that you show, you never actually took the antiderivative before evaluating at x=4 and x=-4
Notably, the answer I got is still not 13 but textbook answer keys are often wrong.
^^
I didn't get 13, either, but it definitely is NOT 0. Look up integrals of even and odd functions.
I wonder how they got 13....
Are you sure your bounds and function are right?
elfprince13 wrote:
In the work that you show, you never actually took the antiderivative before evaluating at x=4 and x=-4
Notably, the answer I got is still not 13 but textbook answer keys are often wrong.
Ok, so if I take this for an exampel: ∫4_-4 (f(x)-3 dx
∫4_-4 (f(x) -3∫4_-4
∫4_-4 (f(x) -3[x]^4_4
∫4_-4 (f(x) - 24
Now I don't understand how to do the last part I have looked at the sulution but I don't understand it completley.
Your mismatched parentheses are killing me.
Can you articulate exactly what is giving you trouble in the last step? What f(x) are you using?
elfprince13 wrote:
Your mismatched parentheses are killing me.
Can you articulate exactly what is giving you trouble in the last step? What f(x) are you using?
Oh, sorry, saw that too, I just did a copy and paste... 
The last step is this:
(-1)(-3-(-4))+2(-1-(-3))+(-3)(2-(-1))+4(4-2)-24=-22
I don't understand it.
lirkaren wrote:
Hi
I have ∫4_-4 f(x) dx that i want to solve.
The primitive function: x²/2
4²/2 - (-4)²/2 = 0
I solved the integral in my Prizm and it returned 0 but te book says the awnser is 13.
If I understand your notation correctly, you have this:
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