If i have a, for example, 3x3 matrix, i declare it like this:

int array [] [3] = { {1,2,3}, {4,5,6},{7,8,9}}

But what if my matrix is like this:

{{1,2},{3,4,5,6,7,8},{1}}


Also, why is this:


Code:


displaying random numbers in printf instead of the array's elements?

also, this:
printf ( "%d %d\n\n", array [1][1], array [1][2]);

displays 5 and 6. what am i doing wrong?

EDIT:
If this is of any help, I used this:

Code:


to display the array, and the rows and columns always have 4 elements

if the number of rows and columns is smaller than 4 in the declaration, some numbers get a random value, if the number is greater or equal to 4, they get 0.

EDIT: Nevermind my second question, I solved it. The first one is still open tho

The main thing that you are doing wrong is counting starting at 1. When you create an array[3], this creates an array of 3 elements, which starts counting from 0.

array[0] is the first element
array[1] is the middle element
array[2] is the last element

Just subtract 1 from you values.

Also, you cannot create an array like {{1,2},{3,4,5,6,7,8},{1}} because the dimensions do not line up. Throw some padding or use a 1D array if need be. Hope this helps!

EDIT: Also, if you want to change the size of your dimensions at runtime, that is also possible without having to specify the size of the array when you compile. If you need this, just ask.

Thanks, that helped