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Math and Science =>
Technology & Calculator Open Topic
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sgm
Calc Guru
Joined: 04 Sep 2003 Posts: 1265
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Posted: 09 Jan 2004 03:57:54 pm Post subject: |
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See Sir Robin's second-to-last post. Nice link though. |
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CoBB
Active Member
Joined: 30 Jun 2003 Posts: 720
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Posted: 13 Jan 2004 04:38:11 pm Post subject: |
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anduril66 wrote:
Yes, you can. Just read what I posted a little above:
e^x = 1 + x + x^2 / 2! + x^3 / 3! + x^4 / 4! + ... (the more members the closer approximation; also if x is close to zero the approximation gets better)
e = lim(n -> inf) (1 + 1/n)^n
See? When calculating e^i, i appears only in the base of powers with integer exponents, which makes it quite easy to determine. Of course this is a purely mathematical approach, not a practical one, since you'd need to evaluate many terms to get a good approximation. |
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thornahawk μολών λαβέ
Active Member
Joined: 27 Mar 2005 Posts: 569
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Posted: 20 Nov 2005 10:58:00 am Post subject: |
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This needs to be moved into the "Math and Science" forum. Can someone be so kind? :)
thornahawk |
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DarkerLine ceci n'est pas une |
Super Elite (Last Title)
Joined: 04 Nov 2003 Posts: 8328
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Posted: 20 Nov 2005 03:10:03 pm Post subject: |
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Done. Now everyone will find out about the topic in which I double-posted. And I've tried so hard to cover it up... |
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thornahawk μολών λαβέ
Active Member
Joined: 27 Mar 2005 Posts: 569
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Posted: 21 Nov 2005 11:22:46 am Post subject: |
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Thank you, DarkerLine. Don't worry, I don't think anyone would begrudge you the multiple post. ;)
Now, since I have done the dirty job of resurrecting the thread, I'd think of trying to add something substantial to this wonderful discussion (belated as it may be).
For starters, the comment re: power series is close, but no cigar. The problem with power series is that the tend to be very accurate only at the center of expansion (i.e. the origin), at the expense of inaccuracy at points so far away.
We first recall symmetries: sine and tangent are odd: sin(x) = -sin(-x), whilst cosine is even: cos(-x) = cos(x). These reflection formulae reduce the problem to evaluating at positive arguments.
We then remember that the trig functions are periodic: sin(x + 2π) = sin(x), and similarly for the cosine and tangent, except that the period is π rather than 2π for tan(). Hence, by subtracting appropriate multiples of the period, the problem reduces to evaluating over a preset range.
Here's the meat: TI apparently uses the so-called CORDIC algorithm, whose discussion I can do no better than point the curious to http://www.cnmat.berkeley.edu/~norbert/cordic/node4.html . If questions still remain, I will be happy to answer them. :)
thornahawk
P.S. Other machines use the so-called "economized Chebyshev approximation", which is effectively replacing the terms of the corresponding power series with appropriate combinations of the Chebyshev polynomials. Google on them for more info. |
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