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Arcane Wizard
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Posted: 12 Dec 2003 10:03:13 am    Post subject:

I've always wondered what they actually do, does anybody happen to know?
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Darth Android
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Posted: 12 Dec 2003 12:36:49 pm    Post subject:

sin( is the function of a sine wave, cos( "" cosine wave, tan( "" tangent wave (?) i think...
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Arcane Wizard
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Posted: 12 Dec 2003 12:43:28 pm    Post subject:

Really? I had no idea. Neutral

Of course I know how to use them, but what do they really do with the number? I mean, what kind of calculations are behind sin/cos/tan?
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b__


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Joined: 16 Jun 2003
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Posted: 12 Dec 2003 02:48:43 pm    Post subject:

Ive never taken trig but i know what they do cause we use them all the time in physics. They are for figuring out different angle measures and sides of a triangle.
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Arcane Wizard
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Posted: 12 Dec 2003 03:23:59 pm    Post subject:

I know what sin/cos/tan are and how to use them, I just want to know what they do exactly with the number you provide when using them.

When you say tan(20/10), for example, you get this nice number, but how does it calculate that number? What exact function can you replace sin/cos/tan with?
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sgm


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Joined: 04 Sep 2003
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Posted: 12 Dec 2003 04:05:34 pm    Post subject:

The trig functions are geometric (link).
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anduril66
Anduril is the Flame of the West!


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Posted: 12 Dec 2003 05:31:17 pm    Post subject:

Does the TI use a formula to calculate sin, cos, and tan, or does it look it up in a table? What are cosh, sinh, and tanh?
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DarkerLine
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Posted: 12 Dec 2003 05:48:32 pm    Post subject:

It might use taylor polynomials to approximate. Example:

sin(x) = x^9/9! - x^7/7! + x^5/5! - x^3/3! + x

cos(x) = x^8/8!- x^6/6! = x^4/4! - x^2/2! + 1

tan(x) = ? not sure ?

the sinh, cosh, tanh are easy.

sinh(x) = (e^x - 1) (e^x + 1)/(2e^x)

cosh(x) = e^x/2 + 1/(2e^x)

tanh(x) = sinh(x)/cosh(x)
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Jeremiah Walgren
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Joined: 24 May 2003
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Posted: 12 Dec 2003 11:52:22 pm    Post subject:

You'd probably want to take a trig related class if you want to have a good definition of what they can do. Basically, like stated before, they're used to figure the measurement of angle. Or, by using the arc of each function (arccos, arcsin, etc), you can figure out a missing side if you have one other side and an angle. Remember, there are certain conditions for each, so don't take this as law or anything. Just a quick summary.

sinh, cosh, tanh, etc, are the hyperbolic trig functions. I have no idea what these are used for.
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KD5YTX


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Joined: 03 Aug 2003
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Posted: 13 Dec 2003 12:55:39 am    Post subject:

In a right triangle, in respect to the angle in question, the sine is the ratio of the opposite side over hypotenuse, cosine is the ratio of the adjancent side over the hypotenuse, and the tangent is the ratio of the opposite side over the adjacent side.

Evil or Very Mad Evil or Very Mad Evil or Very Mad
Reverence abounds over trigonemetric ratios.
Evil or Very Mad Evil or Very Mad Evil or Very Mad
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Jeremiah Walgren
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Posted: 13 Dec 2003 01:05:30 am    Post subject:

Although the functions work for any triangle.
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Arcane Wizard
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Posted: 13 Dec 2003 04:36:22 am    Post subject:

sigma wrote:
The trig functions are geometric (link).

I alerady knew this tricks too, I'm really looking for the exact function of sin, and/or that of cos or tan, preferabbly all of course.

Quote:
Does the TI use a formula to calculate sin, cos, and tan, or does it look it up in a table? What are cosh, sinh, and tanh?
I suppose it uses some kind of formula/function, otherwise there'd have to be thousands (maybe even millions?) of values in some table.

Quote:
sin(x) = x^9/9! - x^7/7! + x^5/5! - x^3/3! + x

cos(x) = x^8/8!- x^6/6! = x^4/4! - x^2/2! + 1
Ah, thanks! That's exactly what I was looking for.

But what about degrees? How is the calculation different 'inside' sin/tan/cos?

Quote:
sinh(x) = (e^x - 1) (e^x + 1)/(2e^x)

cosh(x) = e^x/2 + 1/(2e^x)
Is that like (e^(x-1))(... or like ((e^x)-1)(... ?


Quote:
You'd probably want to take a trig related class if you want to have a good definition of what they can do.
Well, we don't have classes like that, we just have a really busy math class where we get all the subjects together, same goes for physics, chemistry, etc. Our educational system is different, but at least it's one of the best in the world, which is pretty much the only good thing in this coutry (don't even get me started on our software industry, sigh).

Quote:
Basically, like stated before, they're used to figure the measurement of angle. Or, by using the arc of each function (arccos, arcsin, etc), you can figure out a missing side if you have one other side and an angle.
Quote:
In a right triangle, in respect to the angle in question, the sine is the ratio of the opposite side over hypotenuse, cosine is the ratio of the adjancent side over the hypotenuse, and the tangent is the ratio of the opposite side over the adjacent side.
I already knew all that since my first or second year of high-school (~3 or ~4 years ago), I've just been wondering what sin/tan/cos really did, I mean somebody somewhere in the course of history thought of a bunch of functions and called them sin, cos, and tan, but what where those functions exactly?

I haven't had sinh, tanh, or cosh (at least not in that notation), though, they sound interesting.

Thanks to Robin I now know the radian versions of sin and cos, all I'd like to know now is the one for tan and the versions when talking about degrees instead of radians, so does anybody know those?
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CoBB


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Joined: 30 Jun 2003
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Posted: 13 Dec 2003 07:28:35 am    Post subject:

Actually both sin and cos are special cases of the exponential function. Tan is just their ratio.

sin(x) = (exp(ix) - exp(-ix)) / (2i)
cos(x) = (exp(ix) + exp(-ix)) / 2
tan(x) = sin(x) / cos(x)

Hence, if you have the definition of the exponential function, you can derive all the trigs from it:

exp(x) = e^x = 1 + x + x^2 / 2! + x^3 / 3! + x^4 / 4! + ... (the more members the closer approximation; also if x is close to zero the approximation gets better)
e = lim(n -> inf) (1 + 1/n)^n

About degree/radian conversion:

1 deg = (pi / 180) rad
1 rad = (180 / pi) deg

E. g. sin(65 deg) = sin(65 * pi / 180) etc.


Last edited by Guest on 13 Dec 2003 07:41:27 am; edited 1 time in total
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DarkerLine
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Posted: 13 Dec 2003 02:34:49 pm    Post subject:

Arcane Wizard wrote:
But what about degrees? How is the calculation different 'inside' sin/tan/cos?

To do degrees it multiplies the value by 180/pi first to convert to radians.

Quote:
Quote:
sinh(x) = (e^x - 1) (e^x + 1)/(2e^x)

cosh(x) = e^x/2 + 1/(2e^x)
Is that like (e^(x-1))(... or like ((e^x)-1)(... ?


e^(x) - 1

Quote:
I haven't had sinh, tanh, or cosh (at least not in that notation), though, they sound interesting.


They do for hyperbolas (hyperbolae? ) what sin/cos/tan do for circles. For example:

x=sin(t)
y=cos(t)
would graph a circle (x^2 + y^2 = 1).

x=sinh(t)
y=cosh(t)
would graph a hyperbola (x^2 - y^2 = 1).
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DarkerLine
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Posted: 22 Dec 2003 12:24:09 pm    Post subject:

CoBB wrote:
Actually both sin and cos are special cases of the exponential function. Tan is just their ratio.

sin(x) = (exp(ix) - exp(-ix)) / (2i)
cos(x) = (exp(ix) + exp(-ix)) / 2
tan(x) = sin(x) / cos(x)

That is kind of pointless since you'd have to use trig to find e^(i x).


Last edited by Guest on 22 Dec 2003 12:24:31 pm; edited 1 time in total
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CoBB


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Posts: 720

Posted: 04 Jan 2004 05:19:58 am    Post subject:

That's the definition of sin and cos, I can't do anything about it. :)

You can find e^x using e. g. its Taylor series (it's in my post, have you really read it?). That formula remains valid for complex numbers (actually it's valid even if x is a matrix).
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DarkerLine
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Posted: 04 Jan 2004 04:52:39 pm    Post subject:

I'm sure I will understand that by the end of the year, right now I can't.
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sgm


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Joined: 04 Sep 2003
Posts: 1265

Posted: 05 Jan 2004 06:03:07 pm    Post subject:

CoBB wrote:
sin(x) = (exp(ix) - exp(-ix)) / (2i)

If you take out the i's, you get a catenary, right?
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CoBB


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Posted: 07 Jan 2004 04:01:00 am    Post subject:

You need to change the minus to a plus as well.
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anduril66
Anduril is the Flame of the West!


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Joined: 25 May 2003
Posts: 129

Posted: 09 Jan 2004 03:36:24 pm    Post subject:

"You can find e^x using e. g. its Taylor series (it's in my post, have you really read it?). That formula remains valid for complex numbers (actually it's valid even if x is a matrix). "

No, but I would like to. I can't find it. How do you raise a number by i? (w/o usind e^i on a calculator). Reading http://staff.jccc.net/swilson/mathtopics/c...imagandtrig.htm , it seems you have to use cos (and sin).
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