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WhiteDwarf
Newbie
Joined: 10 Nov 2003
Posts: 19
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 Posted: 20 Nov 2003 02:41:52 am Post subject: |
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How could you write a strlen function.... i was thinking some how storing each value place in a list and then refering to the number of elements as a variable or something, but i wouldnt know how to do sometihng like that...and also like the same function to find the number of value places in a number for instance for a dec2hex(); something like
a = user input;
n = strlen(a-1);
dec2hex(a) = a/16^n->a |
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Arcane Wizard
`semi-hippie`
Super Elite (Last Title)
Joined: 02 Jun 2003
Posts: 8993
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| Posted: 20 Nov 2003 09:39:40 am Post subject: |
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strlen = length(string) -> [2ND],[CATALOG],[L], scroll down
intlen = log(int)+1 (int=0=error)
A = user input
N = log(A)+1
dec2hex(A) = A/16^(log(A)+1)->A
EDIT: I just took it all for pseudo-code, but are you sure you're in the right forum?
C++ (not tested, written from memory)
Code:
int strlen(char * a) {
x=0;
while ((a[x] != '\n') && (a[x] != '\0')) { x++; }
return x;
}
Last edited by Guest on 20 Nov 2003 09:43:20 am; edited 1 time in total |
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sgm
Calc Guru
Joined: 04 Sep 2003
Posts: 1265
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| Posted: 20 Nov 2003 01:07:14 pm Post subject: |
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Arcane Wizard wrote: Code: int strlen(char * a) {
x=0;
while ((a[x] != '\n') && (a[x] != '\0')) { x++; }
return x;
}
Code:
int strlen( char * );
int strlen( char *a )
{
int x = 0;
while( (a[x] != '\n') && (a[x] != '\0') )
x++;
return x;
}
Just so it's easier to read, you understand. :)
And just for fun:
Code:
int strlen(char *a)
{
asm {
les di, a ; Probably should be lds si, a — can't remember.
xor cx, cx
mov al, cl
repne scasb
neg cx
mov ax, cx ; Assuming that results are returned in AX.
}
/* Might need to push/pop some registers */
}
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WhiteDwarf
Newbie
Joined: 10 Nov 2003
Posts: 19
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| Posted: 20 Nov 2003 08:27:35 pm Post subject: |
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You can store letters in a list right? like this
{"A", "B", "C", "D","E","F"}-> listA
or would i have to store that into a string, i want to be able to refer to each letter as a location in the list so
Disp listA(3) = "C" |
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JacobdeHaan
Member
Joined: 10 Jul 2003
Posts: 165
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| Posted: 20 Nov 2003 08:34:01 pm Post subject: |
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You can't do that. But by using the sub funcion, you can achieve the same result.
Example:
Code:
sub("ABC",2,1 //this returns the second character in the string, and only one of them
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WhiteDwarf
Newbie
Joined: 10 Nov 2003
Posts: 19
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| Posted: 20 Nov 2003 09:47:58 pm Post subject: |
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lol coding is very frusterating, it seems the more frusterated i get the less i can think and try and think rationally about debuggin, i'm tryin to write a dec 2 hex program
here's what i have, i bet 20 bucks i'm making it alot harder than need be lol
Code:
Input A
: iPart(log(A->B
: For(X,0,B,1
: iPart(A/16->D
: fPart(A/16->->C
: C*16->C
: If C>9: Then
: Disp sub("ABCDEF",C-9,1
: End
: If C<=9: Then
: Disp C
: End
: If 9<D<16: Then
: Disp sub("ABCDEF",D-9,1
: End
: If D<10: Then
: Disp D
: D->A
: End
: End
Is it ok to do this "9<D<16"? or would u use 9<D and D<16 or somthin |
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Darth Android
DragonOS Dev Team
Bandwidth Hog
Joined: 31 May 2003
Posts: 2104
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| Posted: 21 Nov 2003 12:18:10 am Post subject: |
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yup.
counts up to 65536:
[code]DelVar CDelVar DDelVar EDelVar FCLrHome
Input "Dec:",A
"0123456789ABCDEF->Str1
For(B,1,A
C+1->C
If C=16
Then
DelVar CD+1->D
End
If D=16
Then
DelVar DE+1->E
End
If E=16
Then
DelVar EF+1->F
End
Output(1,1,sub(Str1,F+1,1
Output(1,2,sub(Str1,E+1,1
Output(1,3,sub(Str1,D+1,1
Output(1,4,sub(Str1,C+1,1 |
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Darth Android
DragonOS Dev Team
Bandwidth Hog
Joined: 31 May 2003
Posts: 2104
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| Posted: 21 Nov 2003 12:18:43 am Post subject: |
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yup.
counts up to 65536:
Code:
DelVar CDelVar DDelVar EDelVar FCLrHome
Input "Dec:",A
"0123456789ABCDEF->Str1
For(B,1,A
C+1->C
If C=16
Then
DelVar CD+1->D
End
If D=16
Then
DelVar DE+1->E
End
If E=16
Then
DelVar EF+1->F
End
Output(1,1,sub(Str1,F+1,1
Output(1,2,sub(Str1,E+1,1
Output(1,3,sub(Str1,D+1,1
Output(1,4,sub(Str1,C+1,1
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WhiteDwarf
Newbie
Joined: 10 Nov 2003
Posts: 19
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| Posted: 21 Nov 2003 02:26:31 am Post subject: |
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This program doesn't seem to work for me here's my input and output
INPUT Output
1---------->00011
2----------->00012
3------------>00013
150----------->0001150
1000----------->00011000
10000------------>000110000
Last edited by Guest on 21 Nov 2003 02:28:53 am; edited 1 time in total |
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TI-Basic => TI-BASIC
