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+ZERO+


Advanced Member


Joined: 28 Sep 2005
Posts: 289

Posted: 07 Nov 2007 08:57:13 pm    Post subject:

Alrighty, I have tried and tried, but cant seem to get this to a point to which i can program this into a program (im still a little rusty)


Code:
Fb = .159sqrt((Av(1.84x10^8))/(Vb(Lv+.823sqrt(Av))))


Fb = Tuning Frequency (Frequency of box)
Av = Area of Vent (In sq inches)
Vb = Volume of box (in cu inches)
Lv = Length of Vent (Port)(What i want to be alone, so i can just plug it in....)

Any help is much appreciated
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Pseudoprogrammer


Member


Joined: 12 Dec 2006
Posts: 121

Posted: 07 Nov 2007 09:02:47 pm    Post subject:

Input "Area of vent? ",A
Input "Volume of box? ",B
Input "Length of vent? ",C
Disp .159sqrt((A(1.84x10^8))/(B(C+.823sqrt(A))))

I'm not quite sure what your asking... but I think this is what you want... not quite sure.


[ ] Enable emoticons unchecked.


Last edited by Guest on 07 Nov 2007 10:55:25 pm; edited 1 time in total
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+ZERO+


Advanced Member


Joined: 28 Sep 2005
Posts: 289

Posted: 07 Nov 2007 09:08:34 pm    Post subject:

i need to know the length of vent....
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Pseudoprogrammer


Member


Joined: 12 Dec 2006
Posts: 121

Posted: 07 Nov 2007 09:18:37 pm    Post subject:

OH my bad. Oi, the auto smileys messed up my last post too...
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+ZERO+


Advanced Member


Joined: 28 Sep 2005
Posts: 289

Posted: 07 Nov 2007 09:21:00 pm    Post subject:

code boxes! code boxes! code boxes!.... I think i may have gotten it on irc, please check:


Code:
A*(1.84E8)/(V(F/.159)^2)-.823sqrt(A)
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pugboy


Active Member


Joined: 11 Apr 2007
Posts: 544

Posted: 07 Nov 2007 09:22:32 pm    Post subject:

You can uncheck the "Enable Smilies" check box if you want.

Pseudoprogrammer has the right formula for your purposes. You might want to edit that post...


Code:
A(1.84E8)/(V(F/.159)^2)-.823sqrt(A)


You can take out the multiplication symbol after the A


Last edited by Guest on 07 Nov 2007 09:23:56 pm; edited 1 time in total
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Weregoose
Authentic INTJ


Super Elite (Last Title)


Joined: 25 Nov 2004
Posts: 3976

Posted: 08 Nov 2007 01:48:50 am    Post subject:

You could also use: 4651704A/F²/V-.823√(A

Out of curiosity, where did .159, 1.84x10^8, and .823 come from?

I think .159 might be 1/(2[font="times new roman"]π)
, but that's only a hunch.

[EDIT]

I found a good link here.

Last edited by Guest on 04 Sep 2010 11:36:46 pm; edited 1 time in total
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