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Tyraniek
Member
Joined: 07 Jun 2003
Posts: 133
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 Posted: 18 Sep 2003 01:38:20 pm Post subject: |
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I'd like to code a highscore on 16 bits instead of 8.
So that's how I would declare the score :
score .dw 0
Which will create "00 00". Allright. Now, I want to increment it (for exemple, it is equal to FF. But is it "00 FF" or "FF 00" ?). That's how I would increment it :
ld a, (score)
ld h, a
ld a, (score+1)
ld l, a
inc hl
ld (score), hl
Is that right or is there any other way to do it ?
Last question : is it possible to display its value by doing :
ld a, (score)
ld h, a
ld a, (score+1)
ld l, a
B_CALL(_setxxxxop2)
B_CALL(_op2toop1)
B_CALL(_dispop1a)
Thanks for answering  |
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sgm
Calc Guru
Joined: 04 Sep 2003
Posts: 1265
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| Posted: 18 Sep 2003 02:32:48 pm Post subject: |
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:?
ld hl,(score)
inc hl
ld (score),hl |
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Adm.Wiggin
aka Tianon
Know-It-All
Joined: 02 Jun 2003
Posts: 1874
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| Posted: 18 Sep 2003 04:08:31 pm Post subject: |
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| does bcall(_setxxxxop1) use hl, or de? might want to look that up if u dont know already... |
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Justin W.
Shattered Silence
Advanced Member
Joined: 24 May 2003
Posts: 429
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| Posted: 18 Sep 2003 10:16:11 pm Post subject: |
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Adm. Wiggin;
bcall(_setxxxxop2) sets op2 to a floating point integer between 0 and 65535 using hl as the input. |
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Tyraniek
Member
Joined: 07 Jun 2003
Posts: 133
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| Posted: 19 Sep 2003 12:14:31 am Post subject: |
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That's it Justin.
Sigma, I don't agree with you :
By doing "ld hl, (score)", you only store the first byte in (hl).
By doing "inc hl", you just move the pointer, which will point the next byte.
Then, that's the worst, you put the address (for exemple 9E50h) in score and score+1 !!!
So this ode won't work ;-)
Nobody knows how to do ? |
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tr1p1ea
Elite
Joined: 03 Aug 2003
Posts: 870
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| Posted: 19 Sep 2003 01:14:01 am Post subject: |
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Actually what Sigma wrote will work fine.
Here is some code:
Code:
IncreaseScore:
ld hl,(Score) ;hl -> Score
inc hl ;hl -> hl + 1
ld (Score),hl ;Score -> Score + 1
DisplayScore:
ld hl,(0*256)+22 ;penrow = 0, pencol = 22
ld (pencol),hl ;set those coords
ld hl,(Score) ;Score -> hl
bcall(_setxxxxop2) ;hl -> op2
bcall(_op2toop1) ;op2 -> op1
ld a,4 ;max # of chars to display
bcall(_dispop1a) ;display op1 (Score) at penrow, pencol
:)
Last edited by Guest on 19 Sep 2003 01:21:19 am; edited 1 time in total |
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CoBB
Active Member
Joined: 30 Jun 2003
Posts: 720
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| Posted: 19 Sep 2003 06:56:49 am Post subject: |
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Tyraniek wrote: Sigma, I don't agree with you :
By doing "ld hl, (score)", you only store the first byte in (hl).
By doing "inc hl", you just move the pointer, which will point the next byte.
Then, that's the worst, you put the address (for exemple 9E50h) in score and score+1 !!!
So this ode won't work 
This is the most hilarious thing I've read today. You are given the correct solution and you turn it down as if it was erroneous... Probably you should try it first and consult a z80 instruction reference before posting such responses. |
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Tyraniek
Member
Joined: 07 Jun 2003
Posts: 133
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| Posted: 19 Sep 2003 08:35:39 am Post subject: |
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Yes, I'm really confused !!!!
I mistook "ld hl, score" with "ld hl, (score)".
I apologize Sigma. I just noticed it when I left my home. Then I could not edit my post any more.
Really sorry, and thank you for your help.
I apologize. |
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sgm
Calc Guru
Joined: 04 Sep 2003
Posts: 1265
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| Posted: 19 Sep 2003 06:04:22 pm Post subject: |
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CoBB wrote: This is the most hilarious thing I've read today.
No it isn't, this is
Before:
Code:
Msg1:
LD A,'A'
JP Display
Msg2:
LD A,'E'
JP Display
Msg3:
LD A,'Q'
JP Display
Msg4:
LD A,'X'
JP Display
After:
Code:
Msg1:
LD A,'A'
.DB 1
Msg2:
LD A,'E'
.DB 1
Msg3:
LD A,'Q'
.DB 1
Msg4:
LD A,'X'
Display:
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Z80 & 68k Assembly => z80 & ez80 Assembly
