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Advanced Member

Joined: 25 Mar 2009
Posts: 360

Posted: 17 Nov 2009 08:44:06 pm    Post subject:

Okay, it's been a while, but I'm posting on my new algorithm. I have a slight problem.

If this is true:
((N-1) mod x) = x-1
How can I solve via something like Newton's method?

If f(x)=((N-1) mod x)-x+1, what is f'(x)?

Then, what is the simplified version of:
x - f(x)/f'(x)

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