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Flofloflo
Member
Joined: 07 Nov 2007 Posts: 120

Posted: 03 Feb 2009 08:10:16 am Post subject: 


I'm having trouble solving an equation. It has two variables, and both the cosine and sin of one of the variables. I just can't manage to get al the cosine and sines on one side and the velocity on the other... Maybe it's impossible or something...
Here it is:
X^2/Cos^2(a)  (2vxsin(a))/(gcos(a)) = (2hv^2)/G
Now, X G and H are constant values, it doesn't matter where they stand. I've been trying for quite some time, and rewrote it in dozens of ways but I just can't separate V from a
Can anybody help me?? 

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thornahawk μολών λαβέ
Active Member
Joined: 27 Mar 2005 Posts: 569

Posted: 03 Feb 2009 08:31:53 am Post subject: 


Flofloflo wrote: I'm having trouble solving an equation. It has two variables, and both the cosine and sin of one of the variables. I just can't manage to get all the cosine and sines on one side and the velocity on the other... Maybe it's impossible or something...
Here it is:
X^2/Cos^2(a)  (2vxsin(a))/(gcos(a)) = (2hv^2)/G
Now, X G and H are constant values, it doesn't matter where they stand. I've been trying for quite some time, and rewrote it in dozens of ways but I just can't separate V from a
Can anybody help me??
OK... you may have to ensure that your capitalization is correctare x and X, as well as g and G different here?
As it stands, we can simplify some of it:
X˛ sec˛(a)  (2vx/g)tan(a) = 2hv˛/G
It's not too much trouble to solve for the variables in this equation... except for a. As a transcendental equation in the variable a, it is not amenable to closedform solutions. For the other variables, the worst you'd have to do is to use the quadratic equation. :)
thornahawk
Last edited by Guest on 03 Feb 2009 11:36:14 am; edited 1 time in total 

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Flofloflo
Member
Joined: 07 Nov 2007 Posts: 120

Posted: 26 Feb 2009 06:48:35 am Post subject: 


Oops, I'm sorry, I allready solved this one by now, it's just the whole thing was really messy so I didn't figure it all out, but basically I found my formula and all ...
but at least it's good to now I can't possibly solve a That allways annoys me in goniometrics . 

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