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Xeda112358

Active Member

Joined: 19 May 2009
Posts: 520

 Posted: 05 Mar 2010 08:42:07 am    Post subject: Hey y'all, try this: a+bi ClrHome Input "EQU:",Str1 Str1→u ClrHome 3ΔX→B Change this to something like 5ΔX if you want. 3ΔY→C For(X,Xmin-1.5B,Xmax+.5B,2B For(Y,Ymin-1.5C,Ymax+.5C,2C If not(imag(u Line(X,Y,X+B,Y+Cu End End ΔX and ΔY are very useful because they can control the window range, too. These hold the ratio of total window range:#of pixels. 1→ΔY would mean that every time you move the cursor down or up, the Y value decrements or increments 1. Likewise, you can get the current value by using these.Last edited by Guest on 05 Mar 2010 08:46:39 am; edited 1 time in total
thornahawk
μολών λαβέ

Active Member

Joined: 27 Mar 2005
Posts: 569

 Posted: 05 Mar 2010 10:02:37 pm    Post subject: The code in ThunderBolt's post is correct only if you have set ΔY==ΔX; the slope of the lines generated are incorrect otherwise. thornahawk
Xeda112358

Active Member

Joined: 19 May 2009
Posts: 520

 Posted: 08 Mar 2010 10:35:03 am    Post subject: Visually, yes, but mathematically, no. If you're window range is skewed, the graph of the actual equation will look skewed, too. So really, it isn't the slope that is wrong, it is the graph.
thornahawk
μολών λαβέ

Active Member

Joined: 27 Mar 2005
Posts: 569

 Posted: 08 Mar 2010 07:58:14 pm    Post subject: The slope of Line(X,Y,X+B,Y+Cu) == Line(X,Y,X+3ΔX,Y+3ΔYu) is (Y+3ΔYu-Y)/(X+3ΔX-X) == ΔYu/ΔX when it should be just plain u. :| thornahawk
meishe91

Newbie

Joined: 06 Dec 2009
Posts: 49

 Posted: 09 Mar 2010 05:44:46 pm    Post subject: I'm not really following any of that. Last edited by Guest on 09 Mar 2010 05:50:39 pm; edited 1 time in total
Xeda112358

Active Member

Joined: 19 May 2009
Posts: 520

 Posted: 10 Mar 2010 09:00:46 am    Post subject: Gotcha, my bad.
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