Login [Register]
Don't have an account? Register now to chat, post, use our tools, and much more.
This is an archived, read-only copy of the United-TI subforum , including posts and topic from May 2003 to April 2012. If you would like to discuss any of the topics in this forum, you can visit Cemetech's Technology & Calculator Open Topic subforum. Some of these topics may also be directly-linked to active Cemetech topics. If you are a Cemetech member with a linked United-TI account, you can link United-TI topics here with your current Cemetech topics. Math and Science => Technology & Calculator Open Topic
Author Message
Newbie

Bandwidth Hog Joined: 23 Jan 2004
Posts: 2247 Posted: 22 Jan 2009 06:51:24 pm    Post subject: Need help on forming a polynomial whose zeros are -4, -1, 2, 3; degree 4. I know how to solve a degree 3 by foiling and then distributing the third term over the foiled one, but I am confused on how to do 4. I've set the problem up so far: I don't want an answer, just need help on what the next step is. (X+4) (X+1) (X-2) (X-3)
simplethinker
snjwffl

Active Member Joined: 25 Jul 2006
Posts: 700 Posted: 22 Jan 2009 07:21:58 pm    Post subject: You just have to remember the distributive law :) We have p(x) = (X+4)(X+1)(X-2)(X-3). Now, let A=X+4, B=X+1, C=X-2, D=X-3. This gives p(x) = ABCD = (AB)CD = ((X+4)B)CD = (BX+4B)CD = ( X(X+1) + 4(X+1) )CD = ((X^2 + X + 4X + 4)C)D = (CX^2 + CX + C4X + C4)D = ... Just continue that pattern of distributing one term at a time and simplify and you can factor (or un-factor, I always forget which goes which way) any polynomial :biggrin:
Newbie

Bandwidth Hog Joined: 23 Jan 2004
Posts: 2247 Posted: 23 Jan 2009 09:32:23 am    Post subject: Simplethinker thank you so much for your response. That helped me greatly and I was able to get the correct answer. Kudos to you. Better than my math book. lol Anyway the correct answer is: x^4-15x^2+10x+24
simplethinker
snjwffl

Active Member Joined: 25 Jul 2006
Posts: 700 Posted: 23 Jan 2009 01:44:20 pm    Post subject: Newbie wrote:Simplethinker thank you so much for your response. That helped me greatly and I was able to get the correct answer. Kudos to you. Better than my math book. lol Anyway the correct answer is: x^4-15x^2+10x+24 No problem I've only had one teacher that explained it that way, even though it's actually the simplest.
DarkerLine
ceci n'est pas une |

Super Elite (Last Title) Joined: 04 Nov 2003
Posts: 8328 Posted: 23 Jan 2009 01:58:36 pm    Post subject: Here's a more advanced method that might be faster: Start with (X-A)(X-B)(X-C)(X-D). First we want to compute the coefficient of X^4. The only way we can get an X^4 term is if we choose the X term from each factor. The X terms all have a coefficient of 1, so the coefficient of X^4 will be 1*1*1*1=1. Then the coefficient of X^3. To get an X^4 term, we choose the X term for three of the factors, and the constant term from one of the factors. There are four ways to do it: there constant term could be -A (giving -AX^3), -B (giving -BX^3), -C, or -D -- so together, they give (-A-B-C-D)X^3. Then the coefficient of X^2. This is the hardest one. We choose the X term from two factors, and the constant term from the other two. There are 6 ways to do it, which give (-A)(-B)X^2, (-A)(-C)X^2, (-A)(-D)X^2, (-B)(-C)X^2, (-B)(-D)X^2, and (-C)(-D)X^2. So together we get (AB+AC+AD+BC+BD+CD)X^2. Then the coefficient of X. Here, we only choose the X term from one of the factors, so we get all but one of the constant terms each time. This will be (-A)(-B)(-C)X, (-A)(-B)(-D)X, (-A)(-C)(-D)X, and (-B)(-C)(-D)X, for a total of (-ABC-ABD-ACD-BCD)X. Then the constant coefficient. Here, we always choose the constant term, so we'll get (-A)(-B)(-C)(-D) or ABCD. Of course, this method can be used for any number of factors.Last edited by Guest on 23 Jan 2009 01:58:50 pm; edited 1 time in total
thornahawk
μολών λαβέ

Active Member Joined: 27 Mar 2005
Posts: 569 Posted: 26 Jan 2009 12:37:03 pm    Post subject: Short version of DarkerLine's post: you can use Vieta's formulae to form the coefficients of the corresponding monic (that is, the polynomial with 1 as the coefficient of the highest-power term) polynomial given the roots. That makes for a quick check of the coefficient of the next highest power and the constant term: the product of all the roots is the constant term, and the negative of the sum of the roots is the coefficient of the next highest power. For other coefficients, the formulae become more complicated as the polynomial degree goes up. thornahawk
mr. sir

Newbie Joined: 21 Feb 2008
Posts: 41 Posted: 04 Feb 2009 04:36:26 pm    Post subject: Incidentally, I was tired of doing these by hand, and so I decided to write a calc. program for it. If you wish, try to figure out why it works. Code: ```SetUpEditor LCOEF, LROOT ClrList LCOEF, LROOT Prompt N {1->LCOEF For(D,1,N Input "ROOT:",X X->LROOT(D augment(LCOEF,{0})-LROOT(D)augment({0},LCOEF)->LCOEF End For(D,1,N Pause LCOEF(D End```Last edited by Guest on 04 Feb 2009 04:59:00 pm; edited 1 time in total
 Display posts from previous: All Posts Oldest FirstNewest First
Register to Join the Conversation
Have your own thoughts to add to this or any other topic? Want to ask a question, offer a suggestion, share your own programs and projects, upload a file to the file archives, get help with calculator and computer programming, or simply chat with like-minded coders and tech and calculator enthusiasts via the site-wide AJAX SAX widget? Registration for a free Cemetech account only takes a minute.

»
 Page 1 of 1 » All times are GMT - 5 Hours

Advertisement