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Advanced Newbie

Joined: 23 Jan 2008
Posts: 63

Posted: 06 Mar 2008 06:46:27 pm    Post subject:

OK, here it is:

For the standard form of a quadratic equation, find where X1 and X2 are values whose Y-coefficients are equal and X1 is A greater than X2. In other words, make a program that will find the horizontal line that crosses a parabola at two points, which are A units apart.

Good luck, this one flattened me.
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ceci n'est pas une |

Super Elite (Last Title)

Joined: 04 Nov 2003
Posts: 8328

Posted: 06 Mar 2008 06:53:58 pm    Post subject:

This is more of a math problem than a programming problem, isn't it? When y=ax^2+bx+c, you know the vertex is at -b/2a, so all you have to do is and and subtract half of A from this value.
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Advanced Newbie

Joined: 23 Jan 2008
Posts: 63

Posted: 07 Mar 2008 06:39:54 pm    Post subject:

oops, sorry, I meant the reciprocal of A. What I was thinking was, the larger A is, the wider the parabola, so there must be two points that are always the same distance from the vertex that will show, if you were viewing the line without knowing the equation, the value of A. Or at least A^-1.
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