Hi. I am building an adder using regular transistors and i have already built the sum, using 8 transistors (im not using CMOS), exploiting the fact that A XNOR B XNOR C = A XOR B XOR C, which saves me 8 transistors. Now, when i had the more expensive version, the XOR one(that is composed of 4 NAND gates), i was using XORS parts to calculate Carry out. By that i mean that i took the answer of A NAND B, and the answer of first XOR NAND Carry in, and ANDed them(again exploiting the fact that (A NAND B) NAND C = (A AND B) AND C) to get carry out. Now when im using the economic version that saves me 8 transistors, i run into a problem where i dont have the NAND gates, only NOR gates. Is there a cheap way to calculate AND using NOR gates?

EDIT: This is clearly too difficult to understand so i will post a link to a picture i found on the internet.


I think this guy forgot about one cable but it doesnt really matter. As you can see, he used the 2 components of XOR gates to calculate Cout. This cannot be done the same way in my adder because i dont have the NANDs. I tried using boolean logic to find the most optimal solution but i never succeeded. So is there a way to do that?
could you change the google picture link to an actual link to the picture? Thanks Very Happy
So since NOR is basically OR-bar, you can tie the inputs together to make an inverter. If you throw an inverter on each of the inputs of a NOR, you get an AND:

Code:
+-A-+-B-+-a-+-b-+-O-+
| 0 | 0 | 1 | 1 | 0 |
| 0 | 1 | 1 | 0 | 0 |
| 1 | 0 | 0 | 1 | 0 |
| 1 | 1 | 0 | 0 | 1 |
+---+---+---+---+---+
KermMartian wrote:
So since NOR is basically OR-bar, you can tie the inputs together to make an inverter. If you throw an inverter on each of the inputs of a NOR, you get an AND:

Code:
+-A-+-B-+-a-+-b-+-O-+
| 0 | 0 | 1 | 1 | 0 |
| 0 | 1 | 1 | 0 | 0 |
| 1 | 0 | 0 | 1 | 0 |
| 1 | 1 | 0 | 0 | 1 |
+---+---+---+---+---+

I dont think i understand what you said. What do you mean by OR-bar? And by small a and b?
In logic notation, a bar (straight line) over a symbol indicates its negation. Since you can't speak the line over a symbol, you say symbol-bar, and since I can't type a line over symbols on the forum, I wrote OR-bar. What I mean is that NOR is OR with a NOT on the output. In my truth table, a is A-bar and b is B-bar, the states after A and B respectively have been passed through NORs acting as NOTs.
KermMartian wrote:
In logic notation, a bar (straight line) over a symbol indicates its negation. Since you can't speak the line over a symbol, you say symbol-bar, and since I can't type a line over symbols on the forum, I wrote OR-bar. What I mean is that NOR is OR with a NOT on the output. In my truth table, a is A-bar and b is B-bar, the states after A and B respectively have been passed through NORs acting as NOTs.

Okay thank you for the explanation. I think i know what you mean, and that isnt really what i am looking for. I am looking for a way to use the components of the allready existing circut to calculate the carry out. So instead of just calculating the sum, and then calculating AND of 2 inputs and AND of carry in and xor of 2 inputs and then ORing it, which would take 6 transistors total, i want to use some parts of the circut if its possible. I have made a fast drawing of what i allready got.
http://imageshack.us/photo/my-images/850/xnorsum.jpg/
I think im going to stick with the old version. I dont think it can be done so i would only save 4 transistors, and additionally i would have problems with current(dont know the english name, U).

I allways found that minecraft is an awesome tool to analyzing gates and their subcomponents, and in fact it helped me to develop the current version of the circut that you can see on the screenshot above. Just FYI.

Thanks for the help!
That's good to hear; I'm glad you're using Minecraft as an enineering tool. Good luck with your progress on this project, and of course keep us posted.
Well since i was allready done with the version that im using now when i posted this topic, im getting into building this thing, along with the rest of functions(its going to be an ALU).
I have used circut simualtor applet(google it) to simulate it. If you want to take a look at it, be my guest Smile(i know about some mistakes in resistance, ignore that). This is the import(File->Import paste here):

Code:
$ 1 4.9999999999999996E-6 0.015987974607969392 51 5.0 43
t 224 352 256 352 0 1 -0.5974323473734772 0.06310788806324949 100.0
t 224 384 256 384 0 1 0.011454765163800396 0.06541516979988171 100.0
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EDIT: There you go, the mistakes are fixed now Smile
Is something wrong with it? I sence awkward silence
This is the result. The lower part of this circut is the adder. The rest ar e 4 logic operations
http://imgur.com/a/zsVeb
  
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