I am attempting to make a program for solving any equation for its roots using the solve( command, but the correct roots won't show up because of the guess. Is there a way to find the roots without inputting the X.
Also, I start making a program for mean, median, and mode. I have this so far:
Code: ClrHome: Input "# of numbers",A
If A<1
Then: Output(2,1,"Must be greater than 1
Pause:prgrmMMM
Else:A-->dim(L1)
For(B,1,A
Input "N:",N
N-->L1(B)
End:ClrHome
Disp "Range:"
Disp max(L1)-min(L1)
Disp "Median:"
Disp median(L1)
Disp "Mean:"
Disp mean(L1
Disp "mode:"
How can I find the mode of the numbers?
I read that to make a program compatible with MIrageOS and Doors CS you can add this in the beginning of the program:
Code: :DCS
:0123456789ABCDEF
But MirageOS doest pause the program when I need it to. Why doesn't it work?
You can find the mode with a For() loop.
Also, the hex code for the icon must be in quotes (").
souvik1997 wrote:
You can find the mode with a For() loop.
Also, the hex code for the icon must be in quotes (").
How can I use a For( loop to find the mode? Putting the hex code in quotes works! Thanks!
Loop through all the elements of the list and use a counter variable.
After reading this, it inspired me to come up with
this.
Feel free to use it as you please, and please help me optimize it!
I ended up making my own
algorithm for listing all the modes of a set.
Going on-topic, there's a fun little algorithm called the Newton-Raphson method. It repeatedly draws lines that are tangent to the function at a given point and finds out where the line crosses the x-axis, which becomes the new point. This should iterate to the nearest root.
RMMM
technomonkey76 has just edited this program. The source code now reads:
BASIC Code wrote:
:ClrHome
:Input "Numbers? ",N
:If N<2
:Then
:Output(2,3,"Must have 2+
:Output(3,5,"numbers!
:Pause ENTER to quit
:Return
:Else
:SetUpEditorRMMM
:N→dim(∟RMMM
:For(B,1,N
:Input A
:A→∟RMMM(B
:End
:ClrHome
:Disp "Range:",max(∟RMMM)-min(∟RMMM
:Disp "Median:",median(∟RMMM
:Disp "Press ENTER for
:Output(6,7,"more
:Pause
:ClrHome
:Disp "Mean:",mean(∟RMMM
:Disp "Mode:"
:SortA ∟RMMM
:DelVar VDelVar WDelVar YDelVar ZFor(C,1,dim(∟RMMM
:∟RMMM(C→X
:Z+(X=Y)1→Z
:If X≠Y
:X→Y
:If Z>W
:Then
:Z→W
:Y→V
:End
:End
:Disp V
:Pause
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Cemetech
Very nice! Just for the sake of posterity, I have a few tiny suggestions:
Code: :Z+(X=Y)1→Z
:If X≠Y
:X→Y
Why not just this: Code: Z+(X=Y→Z
:X→Y
If X=Y, then :X→Y does nothing; if they're not equal, it will do what it says on the tin. No need to make it conditional. Finally:
Code: :Disp V
:Pause
can just be Pause V.
Here is some code to find the number of occurrences of a number in L1:
Code: sum(seq(L1(X)=<number>,X,1,dim(L1
souvik1997 wrote:
Here is some code to find the number of occurrences of a number in L1:
Code: sum(seq(L1(X)=<number>,X,1,dim(L1
sum(L1=<number>
KermMartian wrote:
souvik1997 wrote:
Here is some code to find the number of occurrences of a number in L1:
Code: sum(seq(L1(X)=<number>,X,1,dim(L1
sum(L1=<number>
/me facepalms >.<
Rohi, you will want to use Kerm's code to check the amount of times a number appears in your list starting from min(L1) to max(L1).
Souvik, it's not like you were wrong or anything; your code was just a bit suboptimal.
KermMartian wrote:
Souvik, it's not like you were wrong or anything; your code was just a bit suboptimal.
I know, it was just a really obvious optimization.
souvik1997 wrote:
KermMartian wrote:
Souvik, it's not like you were wrong or anything; your code was just a bit suboptimal.
I know, it was just a really obvious optimization.
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