I finally finished the program where it starts at zero and counts up to 100!
Code: #include "ti83plus.inc"
.org $9D95
.db $BB,$6D
Start:
LD A, 0
bcall _ClrScrnFull
Loop:
LD H, 0
LD L, A
PUSH AF
bcall _DispHL
bcall _NewLine
POP AF
INC A
CP 101
JR Z, End
JR Loop
End:
ret
As you just pointed out on IRC, this really shouldn't have worked. The following would be correct:
Code: #include "ti83plus.inc"
.org $9D93
.db $BB,$6D
Start:
LD A, 0 ;this should be xor a to save a byte
bcall _ClrScrnFull
Loop:
LD H, 0
LD L, A
PUSH AF
bcall _DispHL
bcall _NewLine
POP AF
INC A
CP 101
JR nZ, Loop ;by changing the logic here, I saved two bytes
; JR Loop
End:
ret
Edit: Since you used only jr (jump relative), with no jumps (jp) nor calls (call), then it actually would have worked even with $9d95 instead of $9d93. 
Also are you sure that _ClrScrnFull preserves the A register? It doesn't say so in the sdk although they usually don't document that kind of stuff well anyway. But just to be safe, I would switch the order so its this:
Code: bcall _ClrScrnFull
ld a,0
and even better, would be to this:
Code: bcall _ClrScrnFull
xor a
Since that's the optimized way to load 0 in a in only one byte.
Ah yes, I'm pretty sure it does nothing of the sort and simply rampages through all the registers. Good catch, Quigibo.
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