@Mexi: Algebra 1 requires no more functionality than a scientific calculator, and barely even that. The most complex thing would be solving a parabola's zeroes with the quadratic equation, a good job for a scientific calculator.
I suppose I'm a bit unfair, since our high school's class goes year-round. We covered u-substitution back in January and have been reviewing for the AP exam since before spring break.
As for the disk/washer methods, Resinator, the thing to remember is that an integral repesents a form of summation. The area of a cross section of the solid is the function that you're integrating. Say you have a solid of revolution, of the line y=x from 0 to 2 revolved around the y-axis. This would be an inverted cone shape. Each cross section has an area of [pi] * x^2. x is your radius because it's half the distance across the cone. So, you integrate [pi]x^2 from 0 to 2 to find the volume. The same applies to the washer method.
Hope I helped!
I suppose I'm a bit unfair, since our high school's class goes year-round. We covered u-substitution back in January and have been reviewing for the AP exam since before spring break.
As for the disk/washer methods, Resinator, the thing to remember is that an integral repesents a form of summation. The area of a cross section of the solid is the function that you're integrating. Say you have a solid of revolution, of the line y=x from 0 to 2 revolved around the y-axis. This would be an inverted cone shape. Each cross section has an area of [pi] * x^2. x is your radius because it's half the distance across the cone. So, you integrate [pi]x^2 from 0 to 2 to find the volume. The same applies to the washer method.
Hope I helped!
