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i am having trouble with this code:


Code:

:ClrDraw
:AxesOff
:CoordOff
:0→Xmin
:94→Xmax
:‾62→Ymin
:0→YMax
:For(A,1,25
:For(B,24,28
:B→L1(A
:End
:End

what i want it to do is store 24-28 into the string five times in that order so that i can make a sprite but when i run it the only number that goes into the list is 28.

Code:
:ClrDraw
:AxesOff
:CoordOff
:0→Xmin
:94→Xmax
:‾62→Ymin
:0→YMax
:For(A,1,25
:For(B,24,28
:B→L1(A+B-24
:End
:End
It stored 24 into each element, then overwrote each element with 25 until they were overwritten with 28.
See my code above. That's the problem - the inner loop actually runs 25 times, not 5 times.
i tried your code. it put 24 25 times than it put 25,26,27,28
Try this:

Code:

:ClrDraw
:AxesOff
:CoordOff
:0→Xmin
:94→Xmax
:‾62→Ymin
:0→YMax
:For(A,0,4
:For(B,24,28
:B→L1(5A+B-23
:End
:End
i put that code in and i got a dimension error.
Sorry. I just realized that and edited my post.

It should be -23 instead of -24
How about:

Code:
:{24,25,26,27,28
:For(A,0,3
:augment(Ans,{24,25,26,27,28
:End
:Ans->L1
thanks. the problem is now fixed

Code:

:1->C:1->A:23->B
:25->dim(L1
:While A<26
:B+C->L1(A
:A+1->A
:C+1->C
:If C=6
:1->C
:End



This code is tested, and does work.
Mine's smaller.
It seems we have three different routines that do the exact same thing. Which one is better?
i think i will use somethings because it is the fastest
Yay. Very Happy Also, there's an optimization for size:

Code:
:{24,25,26,27,28->L1
:For(A,0,3
:augment(Ans,L1
:End
:Ans->L1
More optimization:

:{24,25,26,27,28
:augment(Ans,Ans
:augment(Ans,Ans->L1
That only makes four copies. This should do it

Code:
:{24,25,26,27,28->L
:augment(Ans,Ans
:augment(Ans,Ans
:augment(Ans,L1->L1

I was just thinking wouldn't this be better using strings?

Code:
:"24,25,26,27,28,
:"{"+Ans+Ans+Ans+Ans+Ans+"0->L1

It would be faster working with strings than lists right? The downside is the +"0 is necessary or you'll get a syntax error.
before i go using the strings one let me see if i understand it. the numbers at the top are to get the ans. than ans is used five times to stick it in five times and the 0 terminates string than it gets stored into list one. oh and it is alot faster. i cant even blink and it is done.
That's all there is to it. In fact, since it is much faster I should start using strings to store to lists instead of doing augment( on a list in the Mario source code. I'll see if it helps the Mario program.
tonight i will have to work on code that can delete that last 0 in the list so that it does not interfere with the sprite drawing.
  
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