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What is some good TI-BASIC code for randomly generating a point on the boundary of a square? Assume the square's vertices are at (0,0), (0,1), (1,0), and (1,1) (I'll try and generalize myself), and the point to be generated is stored on (A,B).

I assume I'd have to use rand and some conditional, but I can't begin to guess a nice compact way to do it.

To be clear, I don't mean inside. I mean exactly on the boundary. To avoid confusion.
Found a version.

EDIT:
never mind it's stupid
If the output being in a list variable is okay/desired, I've got this:

Code:
rand(2→L₁
int(2rand→L₁(randInt(1,2
Thanks Runer! I'm having trouble seeing how to generalize it, though. I have a formula for where (A,B) and (C,D) are opposite points on a rectangle, generating a random ordered pair on the rectangle:


Code:
int(2rand
{A+(C-A)(randAns+not(Ans)int(2rand)),B+(D-B)(randnot(Ans)+Ansint(2rand


Any way to improve this? I realize for my special case of a square, it can be simplified a bit.
Assuming a coordinate system (rectangle) from A to X and from B to Y, this code picks a random point on it:

Code:
(X-A)rand+A->PointX:(Y-B)rand+B-Y->PointY
Nik wrote:
Assuming a coordinate system (rectangle) from A to X and from B to Y, this code picks a random point on it:

Code:
(X-A)rand+A->PointX:(Y-B)rand+B-Y->PointY

I meant, on the boundary. A point inside a boundary is easy Razz
Generate a point inside the square and scale it so it lies on the boundary:


Code:
.5-rand(2
.5+.5Ans/max(abs(Ans


I don't know how to elegantly generate points on the rectangle given by (A,B) and (C,D).
  
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