Latest RPG Development - Cemetech | Forum

KermMartian
1
Site Admin (Posts: 64487)

13 Mar 2006 09:25:44 am

Code:

Fill(1,listname

rivereye
Future Admin (Posts: 5546)

13 Mar 2006 09:41:06 am

ok, it is all real variables

KermMartian
1
Site Admin (Posts: 64487)

13 Mar 2006 09:42:38 am

Oh. :S That makes it slightly more complicated. I guess the best thing there is just to 1-->Blah:1-->Etc everything.

rivereye
Future Admin (Posts: 5546)

13 Mar 2006 09:44:55 am

which is what I do (you act like I am stupid here)

KermMartian
1
Site Admin (Posts: 64487)

13 Mar 2006 10:06:08 am

😄 No, I was just trying to think of an optimized way to do it. 🙂

Radical Pi
Member (Posts: 137)

13 Mar 2006 05:04:39 pm

If only this would work:
Code:

For(A,1,10


1 -> expr(sub("BCDEFGHIJK",A,1


End

elfprince13
2
OVER NINE THOUSAND! (Posts: 11880)

13 Mar 2006 08:07:29 pm

💡 💡 💡 💡 💡 💡

Code:




1 -> L1(expr(sub("BCDEFGHIJK",A,1

if it works Im a genius

KermMartian
1
Site Admin (Posts: 64487)

14 Mar 2006 09:01:29 am

ZOMG! I bet it would...

elfprince13
2
OVER NINE THOUSAND! (Posts: 11880)

14 Mar 2006 12:46:27 pm

now I have to test that....and I hope I get credit for thinking of it.

Ive been having fun working with expr( on my frog game

KermMartian
1
Site Admin (Posts: 64487)

14 Mar 2006 12:51:55 pm

expr( is one of the most powreful and least used of TI-BASIC commands.

Radical Pi
Member (Posts: 137)

14 Mar 2006 04:01:37 pm

IT WORKS!!!!! 👍 👍 👍 👍 👍

If dim(L1, of course...

So can you give an example of how to use it? I'm curious about it's potential...

KermMartian
1
Site Admin (Posts: 64487)

14 Mar 2006 04:04:03 pm

How does that work exactly?

elfprince13
2
OVER NINE THOUSAND! (Posts: 11880)

14 Mar 2006 04:07:30 pm

1 -> L1(expr(sub("BCDEFGHIJK",A,1

first, sub picks out the variable you wish to use based on the value of A.
Then expr( evaluates the substring to find the index in the list that you will store too.

Radical Pi
Member (Posts: 137)

14 Mar 2006 04:52:46 pm

I still don't see how it saves space. 😛

KermMartian
1
Site Admin (Posts: 64487)

14 Mar 2006 07:27:34 pm

Wouldn't that be like
1-->L1(B
1-->L1(C

instead of
1-->B
1-->C?

elfprince13
2
OVER NINE THOUSAND! (Posts: 11880)

14 Mar 2006 10:00:41 pm

no, because it allows you to choose which variable to use to store to based on A instead of brute forcing it with If statements.

KermMartian
1
Site Admin (Posts: 64487)

15 Mar 2006 09:41:36 am

I still don't quite see that, but I'll take your word for it. 🙂

elfprince13
2
OVER NINE THOUSAND! (Posts: 11880)

15 Mar 2006 09:57:09 am

you have a bunch of variables that contain list indices. You want to pick which variable to use based on the value of A.

you could either do this:

Code:




1 -> L1(expr(sub("BCDEFGHIJK",A,1

of

Code:




If A = 1


1->L1(B


If A = 2


1->L1(C


If A = 3


1->L1(D


If A = 4


1->L1(E


If A = 5


1->L1(F


If A = 6


1->L1(G


If A = 7


1->L1(H


If A = 8


1->L1(I


If A = 9


1->L1(J


If A = 10


1->L1(K

now do you see the space it saves?

KermMartian
1
Site Admin (Posts: 64487)

15 Mar 2006 10:01:16 am

That's what I thought it did. Fair enough. But I thought we were looking for something to do:
1-->A
1-->B
1-->C....

elfprince13
2
OVER NINE THOUSAND! (Posts: 11880)

15 Mar 2006 12:42:21 pm

right. but if at the start of the program you do:

Code:




10->dim(L1


1->A


2->B


3->C


4->D


5->E


6->F


7->G


8->H


9->I


10->J

you're set 😁