Producing the number 2015 with the smallest code
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Hurray for hyperbolic trig functions! 8 bytes!


Code:
int(-π+e^(cosh(e
That is sech(ξ) indeed.
<- Please Support on Lego Ideas
π/π
While 1
Disp Ans+1
End

Um, is that even a valid solution to this problem?
I program in TI-BASIC and Visual Basic Studio. My programming skills are very basic Very Happy

"We are Anonymous" -Anonymous
Asian wrote:
π/π
While 1
Disp Ans+1
End

Um, is that even a valid solution to this problem?

No, because it uses number tokens. What you could do is this:

Code:
π/π
While π
Ans+int(π-int(e
Disp Ans
End

but that's bigger than runers solution. and it's pretty impractical.

π/π
While π
Ans+π/π
End

New code, I don't actually have a calc or an emulator with me right now. Does it work?
I program in TI-BASIC and Visual Basic Studio. My programming skills are very basic Very Happy

"We are Anonymous" -Anonymous
hehe, this is pretty big and totally impractical, but it works... Razz

π/π+int(πππππ(π/eee)-πππππ(π/e)-ππππ(π/e)-ππππ(π/e)-eee

Since I didn't win the "fewest characters" contest I thought I'd go for "fewest distinct characters".


Code:
ππππππln(πln(πln(πππln(πln(ππln(πln(πln(ππln(πln(ππln(ππln(πππln(ππln(ππln(πππln(ππln(ππ
rounds to 2015 when displayed.
another long solution:

Code:
int(πππππln(πππππe)-eeeint(e)-int(e

I am already amazed by how you got to the very small solutions...
But how the hell did you get to these long solutions? Just trial and error?
  
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