Will the following successfully render an alert message, then write the IP Address in $TARGET to the /etc/hosts.deny file? Platform Linux Ubuntu, 12.04. All variables will be passed as arguments.


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Assuming dialog works like that:

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I just put the variables inside the quote.

Ok, yeah. Never mind. I got it set up to do what I want.

What I would like to happen is to set up a cron job to run a shell script every hour. I know that means I need to use the /etc/cron.hourly directory.

I would like the shell script to look at the contents of a log file, for all entries associated with the process portsentry, with the label "attackalert". But how do I basically get the shell script to know what was in the file last time, and to only show a dialog if there is new content?

The Dialog should basically display the NEW contents of the log file, related to portsentry|attackalert on the screen.

Edit: Here's the script I started on, but I can only imagine whats wrong with it. It syntaxes..


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bump

Well, to start off, you wrote half-Perl, half-Bash code. Pick one or the other (Or at least mix them correctly). Assuming all your code's logic is correct, here is how it would look in Bash:
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Or in Perl:
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Both of those should work and accomplish the same thing you were trying to do.

Ok, so I found on Google that the "|" operator means "or". So to execute grep on two strings, you would do


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I would be willing to execute the two greps separately, but the problem is that I also use the tail command and if I use tail in one command, then call it again, won't it be pointing to the end of the log from the first call?

Edit: I posted in SAX (after looking on the 'man dialogue' page and searching in google ) this question, but had to run... about invoking the "dialog" command from a cron job, with no terminal windows open. Would this open a terminal window to render the dialog GUI, or just do nothing? I see nothing about configuring a "no-terminal" setting for dialog, but I need a pop-up to occur, regardless of whether a terminal is open or not.

Did you actually try dialog from a cron job before asking, your post doesn't make that clear.

You know trying things yourself before asking if it'll work would save everyone a heck of a lot of time.

cron has no idea what the "current" user session is (indeed, multiple sessions may be active simultaneously, or even no user session may be active at any given time), so it cannot open a terminal in an active user session. cron is not particularly useful for interactive tasks like the one you're trying to do.

I wouldn't have asked if I was able to get it working in a cron job. It didn't work. Is there another alternative? I thought of maybe trying to invoke the Ubuntu notification system, but it seems complicated. I'll try the Ubuntu forums for that.

I am trying to write a script for Linux, that takes one argument, and will mount my Mac partition, then set permissions to me if the argument was --mount. If the argument was --unmount, the partition is unmounted from that mount point. I am posting to see if I'm going about it right.


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Looks like you haven't tested that at all, since some things are blatantly wrong (chmod will puke when given a username, and it's 'umount', not 'unmount').

I feel like you'd be better served by a simple fstab entry and static mount point (configured such that you get desired permissions on it), or perhaps autofs.

Anyhow, here's how I might approach this script..
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This is pretty fragile, though, which is why I recommend one of the nicer solutions I mentioned at the top of this post.

Let me play with that a bit.

Edit: It mounts read-only but thats a file system on the OS X side issue. And I have no issue with that. I moved the chown command to after the mount (for some reason that seems to work better). Also, I added a deletion of the media/Macintosh HD directory after the umount command, just to clean up after myself. Lastly, I popped in a 'gksudo nautilus' to open the file viewer as root, so I can view the partition without encountering permission issues with viewing files.


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