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General Coding and Design => General Programming
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bananaman
Indestructible

Calc Guru

Joined: 12 Sep 2005
Posts: 1124

 Posted: 07 Nov 2006 07:51:43 pm    Post subject: I need to know a good algorithm for determining what day of the week the first day of each month occurs. Does anyone know a good one for doing this?
JoeImp
Enlightened

Active Member

Joined: 24 May 2003
Posts: 747

 Posted: 07 Nov 2006 11:42:32 pm    Post subject: http://www.mcs.csuhayward.edu/~malek/Mathlinks/Weekdays.html Use the GetDay function below as needed. Code: ```#include #include #include using namespace std; int GetDay(int day, string month, string year) {    if (year.length() != 4)    {   cout << "Year is out of bounds";   return NULL;    }    int d = day;    int y = atoi(year.substr(2,2).c_str());    int c = atoi(year.substr(0,2).c_str());    int m = -1;    if (month == "March") { m = 1; }    if (month == "April") { m = 2; }    if (month == "May") { m = 3; }    if (month == "June") { m = 4; }    if (month == "July") { m = 5; }    if (month == "August") { m = 6; }    if (month == "September") { m = 7; }    if (month == "October") { m = 8; }    if (month == "November") { m = 9; }    if (month == "December") { m = 10; }    if (month == "January") { m = 11; y--; }    if (month == "February") { m = 12; y--; }    if (m == -1)    {   cout << "Invalid month";   return NULL;    }    return ((d + (int)(floor((2.6 * m) - .2)) - (2 * c) + y + (int)floor(y/4) + (int)floor(c/4))%7); } int main() {    string DayOfWeek[] = { "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday",          "Friday", "Saturday" };    int day;    string month, year;    cout << "Enter day: ";    cin >> day;    cout << "Enter month: ";    cin >> month;    cout << "Enter year: ";    cin >> year;        if (int result = GetDay(day, month, year))    {   cout << "Day of the week: " << DayOfWeek[result];    }    return 0; }``` Sample Execution: Code: ```Enter day: 8 Enter month: November Enter year: 2006 Day of the week: Wednesday```Last edited by Guest on 08 Nov 2006 12:45:11 am; edited 1 time in total
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