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Math and Science => Technology & Calculator Open Topic
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Flofloflo

Member

Joined: 07 Nov 2007
Posts: 120

 Posted: 03 Feb 2009 08:10:16 am    Post subject: I'm having trouble solving an equation. It has two variables, and both the cosine and sin of one of the variables. I just can't manage to get al the cosine and sines on one side and the velocity on the other... Maybe it's impossible or something... Here it is: X^2/Cos^2(a) - (2vxsin(a))/(gcos(a)) = (-2hv^2)/G Now, X G and H are constant values, it doesn't matter where they stand. I've been trying for quite some time, and rewrote it in dozens of ways but I just can't separate V from a Can anybody help me??
thornahawk
μολών λαβέ

Active Member

Joined: 27 Mar 2005
Posts: 569

Posted: 03 Feb 2009 08:31:53 am    Post subject:

 Flofloflo wrote: I'm having trouble solving an equation. It has two variables, and both the cosine and sin of one of the variables. I just can't manage to get all the cosine and sines on one side and the velocity on the other... Maybe it's impossible or something... Here it is: X^2/Cos^2(a) - (2vxsin(a))/(gcos(a)) = (-2hv^2)/G Now, X G and H are constant values, it doesn't matter where they stand. I've been trying for quite some time, and rewrote it in dozens of ways but I just can't separate V from a Can anybody help me??

OK... you may have to ensure that your capitalization is correct-are x and X, as well as g and G different here?

As it stands, we can simplify some of it:

X˛ sec˛(a) - (2vx/g)tan(a) = -2hv˛/G

It's not too much trouble to solve for the variables in this equation... except for a. As a transcendental equation in the variable a, it is not amenable to closed-form solutions. For the other variables, the worst you'd have to do is to use the quadratic equation. :)

thornahawk

Last edited by Guest on 03 Feb 2009 11:36:14 am; edited 1 time in total
Flofloflo

Member

Joined: 07 Nov 2007
Posts: 120

 Posted: 26 Feb 2009 06:48:35 am    Post subject: Oops, I'm sorry, I allready solved this one by now, it's just the whole thing was really messy so I didn't figure it all out, but basically I found my formula and all ... but at least it's good to now I can't possibly solve a That allways annoys me in goniometrics -.-
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