CEMETECH
Leading The Way To The Future
Login [Register]
Username:
Password:
Autologin:

Don't have an account? Register now to chat, post, use our tools, and much more.
Latest Headlines
Online Users
There are 101 users online: 5 members, 72 guests and 24 bots.
Members: gudenau, nsg, Spyro543.
Bots: VoilaBot (2), Spinn3r (1), Magpie Crawler (4), VoilaBot (1), Googlebot (16).
RSS & Social Media
SAX
You must log in to view the SAX chat widget
Author Message
joshie75


Advanced Member


Joined: 09 Nov 2010
Posts: 235
Location: Illinois

Posted: 23 Feb 2012 06:47:24 pm    Post subject: 12V DC power adapter ground

Bored at my grandparents house and had five minutes to kill before we start a puzzle *yay*. So thought I'd ask a quick question so I might have replies when I get home later.

I'm using a 120V AC to 12V DC power converted I scavenged off of an old router. So now that I have the 12V DC I need for my project;
Now what about ground?

Can I use the wire with "-" signs all over it as a ground for all the pieces in my project or?

Here's my circuit.
Back to top
joshie75


Advanced Member


Joined: 09 Nov 2010
Posts: 235
Location: Illinois

Posted: 24 Feb 2012 11:35:36 am    Post subject:

I'm probably not qualified for a double post, but it's regarding my post above.

I tested the adapter with my multimeter;
I secured the wire with the -'s on it to the black tester, and the other wire was secured to the red tester. I got -12v DC. So does this mean the side with the -'s down it is actually positive? Thanks;
Josh
Back to top
benryves


Cemetech Expert


Joined: 12 Aug 2008
Posts: 1357
Location: London, United Kingdom

Posted: 26 Feb 2012 09:23:54 am    Post subject:

The power supply's + terminal should be 12V higher than the - terminal. That is to say that if you use the - terminal as ground (which is typical) then the + terminal is +12V. If you were to use the + terminal as ground then the - terminal would be -12V.

I'm not sure how that's marked; the striped lead might indicate the positive side, not the negative side, though you can confirm this with your multimeter.

Op-amp circuits usually require a dual-polarity power supply, that is one that provides a ground, a positive supply and a negative supply. This is easily achieved by using two batteries:


Code:
  .---o +9V
  |
-----
 ---  9V
-----
 ---
  |
  +---o 0V
  |
-----
 ---  9V
-----
 ---
  |
  '---o -9V

However, if you only have a single-voltage power supply then there are some techniques to generate the negative voltage from the positive one - an easy solution is to use a ICL7660 chip as that does most of the hard work for you.
Back to top
Display posts from previous:   
Register to Join the Conversation
Have your own thoughts to add to this or any other topic? Want to ask a question, offer a suggestion, share your own programs and projects, upload a file to the file archives, get help with calculator and computer programming, or simply chat with like-minded coders and tech and calculator enthusiasts via the site-wide AJAX SAX widget? Registration for a free Cemetech account only takes a minute.

» Go to Registration page
    »
» View previous topic :: View next topic  
Page 1 of 1 » All times are GMT - 5 Hours

 
Jump to:  
You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot vote in polls in this forum

© Copyright 2000-2013 Cemetech & Kerm Martian :: Page Execution Time: 0.021926 seconds.